Question

$\sqrt{ {2}^{8} } ( { {7}^{2} } - {2}^{4} \times 3)$
Va rog urgent! Dau coroana! ​

Answer 1

$\sqrt{2^8}(7^2-2^4\cdot 3) =$

$\sqrt{2^8} = \sqrt{256} = 16$

$16(49-16 \cdot 3)=$

$16 \cdot (49 - 39) =$

$16 \cdot 10 = 160$