Question

$\sqrt{2} x + \sqrt{2} -x= 2- \sqrt{2}$

Answer 1

[tex] \sqrt2{x} + 2\sqrt{2} -x-2=0 x( \sqrt{2}-1 )+2( \sqrt{2}-1 )=0 (\sqrt{2} -1)(x+2)=0 x+2=0 x=-2[/tex]