Question

$\sqrt[3]{16} + \sqrt[3]{54} - \sqrt[3]{128} = ?$

Answer 1

$\sqrt[3]{16}+ \sqrt[3]{54}- \sqrt[3]{128}= 2 \sqrt[3]{2}+3 \sqrt[3]{2}-2^{2} \sqrt[3]{2}=2 \sqrt[3]{2}+3 \sqrt[3]{2}-4 \sqrt[3]{2} = \sqrt[3]{2}$
∛54=∛(2*3³)=3∛2 ...corect