Question

[tex] \sqrt{3}+ \sqrt{12} -3 \sqrt{3} =0
[/tex]

Answer 1

√3 +√12 - 3√ = √12 = √(4*3) - 2√3 = 2√3 - 2√3 = 0

Answer 2

$\sqrt{3} + \sqrt{12}-3 \sqrt{3} =0 \\ \\ \\ \\ \sqrt{3} + 2\sqrt{3}-3 \sqrt{3} =0 \\ \\3 \sqrt{3}-3 \sqrt{3}=0 \\ \\ 0=0$
12=4×3=2²×3 iar√(2²×3)=2√3