Question

$( \sqrt{300} - \sqrt{48} + \frac{1}{3} \sqrt {27} ) : \sqrt{3}$

Answer 1

$=( \sqrt{3*100}- \sqrt{3*16}+ \frac{1}{3 } \sqrt{3*9}): \sqrt{3}=(10 \sqrt{3}-4 \sqrt{3}+ \sqrt{3}): \sqrt{3}=$
$=10 \sqrt{3}: \sqrt{3}-4 \sqrt{3}: \sqrt{3}+ \sqrt{3}: \sqrt{3}=10-4+1=7$