Question

$\sqrt{324 \times ( \sqrt{49 - \sqrt{25) + \sqrt{256} } } }$
$\sqrt{84 - \sqrt{400 + } } \: \sqrt{150 - \sqrt{2500} }$
Am nevoie de ajutor cu exercitiile astea...cine imi da cel mai bun raspuns primeste 100 de puncte,inima si coronita ​

Answer 1

Nu da report please.... Explicație pas cu pas:

a) √(16/25) = √(4^2/5^2) = √(4/5)^2= 4/5

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b) √(81/64) = √(9^2/8^2) =√(9/8)^2= 9/8

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c) √(9/49) = √(3^2/7^2) = √(3/7)^2 = 3/7

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d) √(144/169) = √(12^2/13^2) = √(12/13)^2 = 12/13

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e) √(100/289) = √(10^2/17^2) = √(10/17)^2 = 10/17

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f) √(256/225) = √(2^8/3^2•5^2) = √[2^4)^2/(3•5)^2] = √(2^4/15)^2 = 2^4/15 = 16/15

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g) √(196/289) = √[(2^2•7^2)/17^2] = √[(2•7)^2/17^2] = √(14/17)^2 =14/17

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h) √(625/324) = √[5^4/(2^2•3^4)] = √[(5^2)^2/(2•3^2)^2] = √(5^2/18)^2 = 5^2/18 = 25/18

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i) √(169/156) = √[13^2/(2^2•3•13)] = 13/2√(1/39) = 13/2 • 1√39 = 13√39/2•39 = √39/2•3 = √39/6

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j) √(144/1225) = √(12^2/5^2•7^2) = √[12^2/(5•7)^2] = √(12/35)^2 = 12/35

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k) √(196/324) = √(14^2/2^2•3^4) = √[14^2/(2•3^2)^2] = √(14/18)^2 = 14/18

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l) √(361/484) = √[19^2/(2^2•11^2)] = √[19^2/(2•11)^2 = √(19/22)^2 = 19/22

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^ = simbol folosit pentru ridicarea la putere

/ = linie de fracție