Question

$\sqrt{432}$
cât dă
va rogggg

Answer 1

$\sqrt{432} = \sqrt{2 \times 2 \times 2 \times 2 \times 3 \times 3 \times 3} = \sqrt{(2 \times 2) \times (2 \times 2) \times (3 \times 3) \times 3} = \sqrt{ {2}^{2} \times {2}^{2} \times {3}^{2} \times 3 } = (2 \times 2 \times 3) \sqrt{3} = 12 \sqrt{3}$