Question

$| \sqrt{6} -3|+ \sqrt{6} -4$

$x^{2} - \sqrt{10} +3- \sqrt{x ^{4} } + \sqrt{10}$ unde x apartine R


PT 20 PUNCTE! (2 ex.)

Answer 1

1) $3 - \sqrt{6} + \sqrt{6} - 4 = 3-4=-1$
2) $x^{2} - \sqrt{10} + 3- x^{2} + \sqrt{10} = 3$