Question

$( \sqrt{7 - 2 \sqrt{6 - \sqrt{7 + 2 \sqrt{6) {?}^{2} } } } } .$
$(2x - 7) {?}^{2} - (3x - 1)(3x + 1) - (x + 3) {?}^{2}$
$3x \times (2x - 1) - 4 \times (x {?}^{2} - 2x - 2$
$(x - 8)(2x - 9)$
$(2 - 3x) \times (2 + 3x)$
$(2 \sqrt{2x} + \sqrt{3) {?}^{2} } - ( \sqrt{3x - 2 \sqrt{5} }) {?}^{2} - ( \sqrt{2x} + \sqrt{5} \times ( \sqrt{2x} - \sqrt{5}$
$(6 - 2 \sqrt{5} - \sqrt{6 + 2 \sqrt{5 { = }^{2} } }$

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Answer 1

Daca avem radical la a 2 inseamna ca vom scapa de radical

la prima nu stiu, pt ca nu imi da

b) 4x²-28x+49-9x²-1-x²-6x-9= -6x²-34x+38

c) 6x²-3x-4x²+8x+8= 2x²+5x+8

d)2x²-9x-6x-9x²= -7x²-15x

e) 4*2x²+4√6x+3-(3x-2√5)-(2x²-5)= 8x²+4√6x+3-3x+2√5-2x²+5= 6x²+4√6x-3x+2√5+8

f) nu stiu