Question

$\sqrt{8} + \sqrt{32} - \sqrt{50} =$

Answer 1

$\sqrt{8} + \sqrt{32}+ \sqrt{50}=$$\sqrt{2}$
$= \sqrt{4*2}+ \sqrt{16*2}- \sqrt{25*2}$
$= \sqrt{4}* \sqrt{2} + \sqrt{16}* \sqrt{2}- \sqrt{25}* \sqrt{2}$
$=2 \sqrt{2}+ 4\sqrt{2}-5 \sqrt{2}$
$=(2+4-5) \sqrt{2}$
$=(6-5) \sqrt{2}$
$=1 \sqrt{2}$
$= \sqrt{2}$