Question

$\sqrt{ \frac{x^2}{25} }- \sqrt{ \frac{y^2}{16} }=$

Answer 1

$\frac{ \sqrt{ x^{2} } }{5} - \frac{ \sqrt{ y^{2} } }{4} = \frac{x}{5} - \frac{y}{4} = \frac{4x-5y}{20}$

Answer 2

   
[tex]\displaystyle \sqrt{ \frac{x^2}{25} }- \sqrt{ \frac{y^2}{16} }= \frac{x}{5}- \frac{y}{4} = \boxed{\frac{4x-5y}{20} } [/tex]