Question

$( \sqrt{x} + \frac{9}{x} )^{9} , x\ \textgreater \ 0$
Aflati $T _{k+1}$ care nu contine x

Answer 1

Tk+1=C din9 luate cite k*(√x)^(9-k)*(9*x)^k
(9-k)/2-k=0⇒9-3k=0⇒k=3
deci T3+1 nu contine pe x
T4=C din 9 cite 3 *x^3*x^(-3)=84