Question

[tex] \sqrt{x} =x+1
\\ \sqrt{5-x} + \sqrt{x-6} =x \\ ( x^{3} -1)* \sqrt{ x^{2} +7x+12} =0
\\ \sqrt{x+3} =x-1 \\ \sqrt{2x+5} - \sqrt{3x-5} =2 \\
(2 x^{2} -x-1)* \sqrt{ x^{2} -64}=0
\\ va rog frumas ajutatima sa rezolv aceste 6 inecuatrii[/tex]

Answer 1

$\sqrt{x} =x+1\Longleftrightarrow x=x^2+2x+1 \Longleftrightarrow x^2+x+1=0$