Question

$\sqrt12 x^{2} - \sqrt32x- 4 \sqrt3 x^{2} + \sqrt50x$           
VA ROG > REPEDE

Answer 1

$\sqrt{12} x^{2} - \sqrt{32}x-4 \sqrt{3} x^{2} + \sqrt{50}x= \sqrt{4*3} x^{2} - \sqrt{16*2}x -4 \sqrt{3} x^{2} + \\+\sqrt{25*2}x=2 \sqrt{3} x^{2} -4 \sqrt{2}x- 4 \sqrt{3} x^{2}+5 \sqrt{2}x= \sqrt{2}x-2\sqrt{3} x^{2}=\\=x(\sqrt{2}-2\sqrt{3}x)$