Question

$x^{2} + (1+ \sqrt{3} ) x + \sqrt{3} = 0$

Answer 1

Δ=$(1+ \sqrt{3}) ^{2} -4*1* \sqrt{3}=1+2 \sqrt{3}+3-4 \sqrt{3}=4-2 \sqrt{3 } = (\sqrt{3}-1)^2 \\ x_{1}= \frac{1+ \sqrt{3}- \sqrt{3}+1 }{2} =1 \\ x_{2}= \frac{1+ \sqrt{3}+ \sqrt{3}-1 }{2}= \sqrt{3}$