Question

$<var>x^{2}-3x+1=5</var>$

Answer 1

[tex]delta= b^{2} -4ac[/text]
x^{2}-3x-4=0
delta=9+16=25
x1=(-b+radical din delta)/2a
x1=(3+5)/2=8/2=4
x2=(-b-radical din delta)/2a
x2=(3-5)/2=-2/2=-1