Question

${x}^{2} - 3x - 18 = 0$
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Answer 1

x²-3x-18=0

a=1

b=-3

c=-18

delta=b²-4ac

delta=9+4×18

delta=9+72

delta=81

x1=(-b-rad din delta)/2a

x1=(3-9)/2

x1=6/2

x1=3

x2=(-b+rad din delta)/2a

x2=(3+9)/2

x2=12/2

x2=6