Question

$(x \sqrt{2}+1) ^{2} , (x \sqrt{2}+1)(x \sqrt{2}-1)$ PAs cu pas va rog

Answer 1

(x√2+1)²=(x√2)²+2·x√2·1+1²=2x²+2x√2+1

(x√2+1)(x√2-1)=(x√2)²-1²=2x²-1

aplici formula   (a+b)²=a²+2ab+b²
                       (a+b)(a-b)=a²-b²

Answer 2

 [tex]la \;exercitiul \;1\;,\; folosim\;formula:\;(a+b)^2=a^2+2*a*b+b^2\\ (x\sqrt2+1)^2-(x\sqrt2)^2+2*(x\sqrt2*1+1^2=2x^2+2\sqrt2\;x+1\;;\\ la\;ex.\; 2\;,\;folosim\; formula:(a+b)(a-b)=a^2-b^2\;;\\ (x\sqrt2+1)(x\sqrt2-1)=(x\sqrt2)^2-1^2=2x^2-1\;; [/tex]