Question

$x+y+z \geq \sqrt{xy} \sqrt{xz} \sqrt{yz}$
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Answer 1

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xy+xz≥2xyxz‾‾‾‾√=2xyz‾‾√,xy+yz≥2yxz‾‾√,xz+yz≥2zxz‾‾√.xy+xz≥2xyxz=2xyz,xyyz≥2yxz,xz+yz≥2zxz.+