Question

$z = 1 + i +{i}^{2} + {i}^{3} + {i}^{4} + {i}^{5} + {i}^{6}$
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Answer 1

$z = 1 + {i}^{2} + {i}^{3} + {i}^{4} + {i}^{5} + {i}^{6}$

$z = 1 - 1 + {i}^{2} \times i + {( {i}^{2}) }^{2} + {i}^{2} \times {i}^{3} + {( {i}^{2} )}^{3}$

$z = 0 + ( - 1) \times i + {( - 1)}^{2} + ( - 1) \times {i}^{3} + {( - 1)}^{3}$

$z = - i + 1 + ( - 1) \times ( - i) - 1$

$z = - i + i$

$z = 0$

Answer 2

Salut,

z=1+i^2+i^3+1^4+1^5+1^6=

z=1-1+i^2×i+(i^2)^2+i^2×i^3+(i^2)^3=

z=0+(-1)×i+(-1)^2+(-1)×i^3+(-1)^3=

z=i+1+(-1)×(-i)-1=

z=-i+i

z=0

^ inseamna la putere

$by \\ 7646$