Question

tg(x)=? x- unghi ascutit sin (x) =$\frac{5}{13}$

Answer 1

$tg (x) = \frac{sin (x)}{cos(x)} \\ \\ sin^{2} (x)+ cos^{2} (x) = 1 \\ \\ cos(x) = \sqrt{1-sin^{2}(x)} \\ \\ cos(x) = \sqrt{1- \frac{25}{169} } \\ \\ cos (x) = \sqrt{ \frac{169-25}{169} } \\ \\ cos(x) = \sqrt{ \frac{144}{169} } \\ \\ cos (x) = \frac{12}{13} \\ \\ tg(x) = \frac{ \frac{5}{13} }{ \frac{12}{13} } \\ \\ tg(x) = \frac{5}{13} * \frac{13}{12} \\ \\ tg(x) = \frac{5}{12} \\ \\ Sper~ca~te-am~ajutat!$