Question

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Answer 1

1.a.1/2 , 2/4, 3/6, 4/8, 5/10
b.3/1, 6/2, 9/3
c.1/3, 3/5, 5/7, 7/9
d. 2/1, 4/1, 6/1, 8/1, 10/1, 4/2, 6/2, 8/2, 10/2, 4/3, 6/3, 8/3, 10/3, 6/4, 8/4, 10/4, 6/5, 8/5, 10/5, 8/6, 10/6, 8/7, 10/7, 10/9

2. a) 2 timpi
b) Patrimea, 1 timp

3. 3/4y=6. y=6x4/3=8 m

4.180=2/5y y=5x180/2=450 l
 
5. 648x3/9=216 visini

648-216=432 pomi ramasi

432x3/6=216 caisi

432-216=216 pomi ramasi

216/4=54 pruni

216-54=162 ciresi

Answer 2

1.
a)2/4; 3/6; 4/8;5/10.;b)3/1, 6/2, 9/3. c)1/3,3/5,5/7,7/9, d)4//2,4/3, 6/2,6/3,6/4,6/5,8/2,8/3,8/4,8/5,8/6,8/7.10/2,10/3,10/4,10/5,10/6,10/7,10/8,10/9.
2.
1/2*4=4/2=2
1/4*4=4/4=1
3.
3/4*x=6; 3x/4=6;3x=6*4; x=8 sfoara are 8m
4.
2/5*x=180; 2x=5*180; x=450 ; butoiul are 450 litri
5.
3/9*648= 648/3=216 visini; 648-216= 432 restul de pomi
3/6*432=432/2= 216 caisi; 432-216 =216 restul de pomi
1/4*216=216:4= 54 pruni; 216-54= 162 restul de pomi sunt ciresii
6.
5/7*x=630; 5x=630*7 ; x=630*7/5; x=882 flori
7.
3/8*504= 3*504/8=189
2/8*504=2*504/8=126
504-189-126=189 ziare ramase
8.
compunere problema

Un taran aduce la piata o remorca de 720 kg de cartofi. Dimineata vinde 1/3 din cartofi, iar dupa amiaza, 4/6 din cartofi. Câte kilograme ii ramân seara,

Rezolvare:
1/3*720=720/3=240
4/6*720=480
720-240-480= 0 kg cartofi ramasi