Question

Totul in poza ! Clasa a -VII-a , cred ca trebuie sa rationalizati .Multumesc !

Answer 1

mai intai scoti de sub radical
√54=3√6
√24=2√6
√96=4√6
√216=6√6
√12=2√3
√32=4√2
√3(9/3√6-4/2√6)-√2(8/4√6-18/6√6)+1/12(2√3-4√2)=
√3(3/√6-2/√6)-√2(2/√6-3/√6)+2√3/12-4√2/12=
√3*1/√6+√2*1/√6+√3/6-√2/3=
√3/√2√3+√2/√2√3+√3/6-√2/3=
1/√2+1/√3+√3/6-√2/3=
√2/2+√3/3+√3/6-√2/3=
3√2/6-2√2/6+2√3/6+√3/6=
√2/6+3√3/6