Question

transforma in scara celsius urmatoarele temperaturi:
a) T= 73K
b) T= 290 K
c) T= 400 K

Answer 1

T(K)=t(C) + 273=>t(C)=T(K) - 273
T=73=>t(C)=73-273=>t(C)= - 200 grade
T=290=>t(C)=290-273=>t(C)= 17 grade
T=400=>t(C)=400-273=>t(C)= 127 grade