Question

transformand 2,1(3) in fractie ordinară ireductibila obtinem??

Answer 1

[tex]2,1(3)=\frac{213-21}{90}=\frac{192}{90}=\frac{96}{45}=\frac{32}{15}\\ sau\\ 2,1(3)=2\frac{13-1}{90}=2\frac{12}{90}=2\frac{192}{90}=\frac{96}{45}=\frac{32}{15}[/tex]