Question

transformati in factori ireductibili:0,8;1,(3);0,2(6)

Answer 1

$0.8 = \frac{8}{10} = \frac{4}{5}$

$1.(3) = \frac{13 - 1}{9} = \frac{12}{9} = \frac{4}{3}$

$0.2(6) = \frac{26 - 2}{90} = \frac{24}{90} = \frac{12}{45} = \frac{4}{15}$