Question

Transformati in fractie zecimala periodica:
0,42+0,92-0,52
(3,5:0,5+1,2)*2-1,4
[(3*2+3*4):(23-20)+4*3+2]*2-25
{1+2*[3+4*(5*6+7)]}÷3-100

Answer 1

a) 0,42+0,92-0,52 = 0,82
b) (3,5:0,5+1,2)*2-1,4= (6,+1,2)*2-1,4= 7,3*2-1,4= 14,6-1,4= 13,2
c) [(3*2+3*4):(23-20)+4*3+2]*2-25 = [(6+12) :3+4*3+2]*2-25]= (18:3+4*3+2)*2-25=(6+12+2)*2-25=20*2-25= 40-25= 15
d ) {1+2*[3+4*(5*6+7)]}÷3-100= {1+2*[3+4*(30+7)]}÷ 3-100= [1+2*(3+4*37)]÷3-100= (1+2*151)÷3-100= 303 ÷3 -100=101-100 = 1