Question

Transformati in fractii ireductibile.

A) 2.(3)
B) 1.(23)
C) 0.(122)
D) 2.1(3)
E) 3.2(6)

Answer 1

Răspuns:

Explicație pas cu pas:

2,(3) = (23 - 2)/9 = 21/9 = 7/3

1,(23) = (123 - 1)/99 = 122/99

0,(122) = 122/999

2,1(3) = (213 - 21)/90 = 192/90 = 64/30 = 32/15

3,2(6) = (326 - 32)/90 = 294/90 = 49/15

Answer 2

a) 2,(3)=(23-2)/9=21/9=7/3

b) 1,(23)=(123-1)/99=122/99

c) 0,(122)=122/999

d) 2,1(3)=(213-21)/90=192/90=64/30=32/15

e) 3,2(6)=(326-32)/90=294/90=98/30=49/15