Question

Transformați in fracții ordinare ireductibile: a)12,6 b)2,25
c)0,(3)
d)5,(72)
e )3,7(27)
f)1,08(3)

Answer 1

0,(3)=$\frac{3}{9} = \frac{1}{3}$
5,(72) =$\frac{572-5}{99} = \frac{ 567}{99}= \frac{63}{11}$
3,7(27)=$\frac{3727-37}{990} = \frac{3690}{990} = \frac{41}{11}$
1,08(3)=$\frac{1083-108}{900}= \frac{975}{900}= \frac{13}{12}$