Question

Transformați următoarele fracții zecimale in fr ordinare ireductibile 10,8; 3,25; -0(3); 1,(54); 0,2(7); 2,6(1);

Answer 1

$\displaystyle 10,8= \frac{108}{10} ^{(2} = \frac{54}{5} \\ \\ 3,25= \frac{325}{100} ^{(25} = \frac{13}{4} \\ \\ -0,(3)=- \frac{3}{9} ^{(3} =- \frac{1}{3} \\ \\ 1,(54)= \frac{154-1}{99} = \frac{153}{99} ^{(9} = \frac{17}{11} \\ \\ 0,2(7)= \frac{27-2}{90} = \frac{25}{90} ^{(5} = \frac{5}{18} \\ \\ 2,6(1)= \frac{261-26}{90} = \frac{235}{90} ^{(5} = \frac{47}{18}$