Question

Transfornați în fracții ordinare ireductibole: 2,4; 0,(6); 1,15; 2,(12); 0,3(6); 0,1(13).

Answer 1

2,4=24/10=12/5;
0,[6]=6/9=2/3;
1,15=115/100=23/20;
2,[12]=212-2/99=210/99=70/33;
0,3[6]=36/90=12/30=2/5;
0,1[13]=113-1/990=112/990=56/495;

Answer 2

 [tex]2,4=\frac{24}{10}=12/5\;\;;\;\;0,(6)=\frac{6}{9}=\frac{2}{3};\\ 1,15=\frac{115}{100}=23/20\;\;\;;\;\;2,(12)=\frac{212-2}{99}=\frac{210}{99}=70/33\;;\\ 0,3(6)=\frac{36-3}{90}=\frac{33}{90}=11/30\;\;\;;\;\;0,1(13)=\frac{113-1}{990}=\frac{112}{990}=56/495\;;[/tex]