Question

Trapezul ABCD are. AB// CD, AB=15cm , CD=18, AD=8cm si BC =10cm. Daca  AD reunit cu BC= {E}, calculati perimetrul  triunghiului EAB. 

Answer 1

EA/ED=EB/EC=AB/DC
EA/(EA+AD)=EB/(EB+BC)=AB/DC
EA/(EA+8)=EB/(EB+10)=15/18=5/6

EA/(EA+8)=5/6
6EA=5EA+40
EA=40

EB/(EB+10)=5/6
6EB=5EB+50
EB=50

P EAB=EA+AB+EB=40+15+50=105

Answer 2

EA/ED=EB/EC=AB/DC
EA/(EA+AD)=EB/(EB+BC)=AB/DC
EA/(EA+8)=EB/(EB+10)=15/18=5/6

EA/(EA+8)=5/6
6EA=5EA+40
EA=40

EB/(EB+10)=5/6
6EB=5EB+50
EB=50