Question

Trapezul ABCD are AB ||CD , AB=16 CM , BC = 10cm ,DB _|_ BC ,DC =20 CM ,AO _|_DB,O apartine lui Db.Aflati perimetrul patrulaterului ABCO ..Am nevoie urgent de ajutor,va rog ajutati-ma!!! :(( 

Answer 1

ΔCBD cu ∧CBD=90*cu pitagora
BD²CD²-CB²=400-100=300
BD=10√3
daca bc=1/2.CD⇒∧CDB=30*
AB||CD intersectate cu BD⇒∧CDB≡∧DBA=30*
ΔBOA dreptunghic⇒OA=AB/2=8
BO²=AB²-OA²=256-64=192
OB=8√3
in tr drept BCO CO²=CB²+BO²=100+192=292
CO=2√73
P=2√73+8√3+10+16