Question

Trapezul dreptunghic ABCD cu AB // CD A=90 si D 90 si B =45 digonala AC perpendicular pe BC BC =16 cm calculati perimetrul

Answer 1

ΔABC -dr.isoscel (∡C=90° ∡B = 45°) => AB = 16√2 cm

CE ⊥ AB => (T45°) => CE = AB/2 = 16√2/2 = 8√2 cm

CE = AD => AD = 8√2 cm

CE - mediana => AE = AB/2 = 16√2/2 = 8√2 cm

AE = DC => DC = 8√2 cm

P = AB+BC+CD+DA = 8√2 + 16 + 8√2 + 8√2 = 24√3 + 16 cm