Question

treceti in baza 10 urmatoarele numere naturale: A) 10001 in baza 2 B)101011 in baza 2

Answer 1

10001 in baza 2 = 2^0 x 1 + 2^1 x 0 + 2^2 x 0 + 2^3 x 0 + 2^4 x 0 = 1 + 16 = 17

101011 in baza 2 = 2^0 x 1 + 2^1 x 1 + 2^2 x 0 + 2^3 x 1 + 2^4 x 0 + 2^5 x 1 = 1 + 2 +8 + 32 = 43

de la dreapta la stanga inmultesti cifra 1 cu 2^0, cifra 2 cu 2^1, cifra 3 cu 2^2 .....

Answer 2

10001₍₂₎  = 2⁰ · 1 + 2¹· 0 + 2²· 0 + 2³ · 0 + 2⁴· 0 = 1 + 16 = 17₍₁₀₎

101011 ₍₂₎ = 2⁰ · 1 + 2¹ · 1 + 2² · 0 + 2³·1 + 2⁴· 0 + 2⁵ · 1 = 1 + 2 +8 + 32 = 43₍₁₀₎