Question

Trei molecule de acetona se condenseaza crotonic dupa schema:A(cc)+A(cm)+A(cc),unde cc si cm reprezinta componenta carbonilica si metilenica. Produsul obtinut aditioneaza 2 moli de clor si apoi este redus cu sodiul si alcool. Produsul final este?

Answer 1

(CH3)2C=O+CH3COCH3 +O=C(CH3)2⇒ CH3-(CH3)C=CH-CO-CH=C(CH3)-CH3
+ 2Cl2 ⇒CH3-(CH3)CCl-HCCl-CO-CHCl-ClC(CH3)-CH3 ⇒
CH3-(CH3)CCl-HCCl-CH(OH)-HCCl-ClCH(CH3)CH3