Question

trei nr au suma 38.daca scad din primul nr 5 si din al doilea 3,nr devin egale.afla fiecare nr?

Answer 1

(38-5-3)/3=10 al doilea numar
10+5=15 primul numar
10+3 al treilea numar

Answer 2

$x+y+z=38 \\ x-5=y-3=z \\ x=5+(y-3) \\ 5+(y-3)+y+(y-3)=5+y+2(y-3)=38 \\ y+2y-6=38-5=33 \\ 3y-6=33 \\ 3y=6+33=39 \\ y=\frac{39}{3} \\ \boxed{\bold{y=13}} \\ x=5+(y-3)=5+(13-3)=5+10 \\ \boxed{\bold{x=15}} \\ z=y-3=13-3 \\ \boxed{\bold{z=10}}$