Question

Trigonometrie

Salut, am de rezolvat sin(2x)=0.Rezolvarea mea:

$sin(2x)=0$
$2x=t$
$sint=0$
$t=k\pi ,kZ$
$2x=k \pi$
$x= \frac{k \pi }{2},k Z$

Unde gresesc ?

Answer 1

Hello, tu ai inceput corect, nu inteleg cum ai ajuns la egalitatea: t = k/pi, uite cum as rezolva eu:
sin 2*x = 0, t = 2*x.
sin t = 0 <=> t = (-1)^k*arcsin 0 + pi*k, k € Z.
t = 0 + pi*k = pi*k, k € Z.
2*x = pi*k, k € Z.
x = pi*k/2, k € Z.
Raspuns: x = pi*k/2, k € Z.

Sper ca ai inteles!