Question

triplul lungimii unui segment [AB] depaseste cu 25u.m. jumatatea lungimii acestuia.Ce lungime are segmentul[AB?]

Answer 1

l- latura AB
3l=25 + $\frac{l}{2}$
3l- $\frac{l}{2} = 25$ 
Dupa ce aduci la acelasi numitor (2) = 6l -l = 50 
5l= 50=> l= 50 : 5 => l=10 u.m 

Answer 2

[tex]3*[AB]-25=[AB]:2 =\ \textgreater \ 2*(3*[AB]-25)=[AB] adica 6*[AB]-50= [AB] = 6*[AB]-[AB]=50 deci [AB] =10 u.m[/tex]