Question

triplul sumei a trei numere este 282;
sa se afle numerele stiind ca primul este cu 26 mai mic decat al doilea si mai mare decat al treilea cu 28.

Answer 1

a + b + c = 94
a = b - 26
a = c + 28
94 + 26 - 28 => 96 : 3 = 32
a = 32
b = 58
c = 4

Answer 2

$3(a+b+c)=282 \ |:3 \\\\ a+b+c=94 \\\\\\ b=a+26 \\\\ c=a-28 \\\\ a+26+a+a-28=94 \\\\ 3a-2=94 \\\\ 3a=94+2 \\\\ 3a=96 \ |:3 \\\\ \boxed{a=32} \\\\ b=32+26 \\\\ \boxed{b=58} \\\\ c=32-28 \\\\ \boxed{c=4}$