Question

Triunghiul ABC.....​

Answer 1

tgB=AC/AB

tgB=sinB/cosB=(3/5)/(√(1-9/25))=(3/5)/(4/5)=3/5*5/4=3/4

3/4=AC/16⇒AC=4*3=12(cm)

A=(12*16)/2=12*8=96(cm²)

Lm=BC/2

cosB=AB/BC⇒4/5=16/BC⇒BC=20

Lm=20/2=10(cm)

Bafta!