Question

Triunghiul ABC dreptunghic in A. AB=40, BC=50.
AC=?
sinB=?
cosB=?
tgB=?​

Answer 1

La primul punct am aplicat teorema lui Pitagora, sper sa te ajute!

Answer 2

(30,  40,  50) - triplet pitagoreic ⇒ AC = 30

$\it sinB=\dfrac{AC}{BC}=\dfrac{^{2)}30}{\ 50}=\dfrac{60}{100}=0,6\\ \\ \\ cosB=\dfrac{AB}{BC}=\dfrac{^{2)}40}{\ 50}=\dfrac{80}{100}=0,8\\ \\ \\ tgB=\dfrac{AC}{AB}=\dfrac{^{25)}30}{\ \ 40}=\dfrac{750}{1000}=0,75$