Question

Ttei frati au impreuna 27 de nuci.In pauza mare Mihai mananca 7 nuci,Ionel mananca 5 nuci iar Alin mananca 6 nuci.Dupa pauza mare fiecare a ramas cu acelasi numar de nuci.Cate nuci avea initial Ionel?

Answer 1

7+5+6=18 nuci mancate  27-18=9 nucu ramase namancate  9impartit la 3=3 avea fiecare in plus,7+3=10,5+3=8,6+3=9.

Answer 2

7+5+6=18 nuci mancate
27-18=9 nuci ramase nemancate 
9:3=3 avea fiecare in plus
7+3=10 avea Mihai
5+3=8 avea Ionel
6+3=9 avea Alin
  Raspuns:8 nuci avea Ionel