Question

u(7⁴⁷⁵);u(7²³⁶) u(8¹⁰³¹);u(8²⁶⁰) u(9⁹³); u(9¹⁵⁰)
Vă rog am nevoie urgent de ajutor!!!​

Answer 1

Răspuns:

Explicație pas cu pas:

Un nr. terminat cu 1 sau 5 sau 6, la orice

putere, se termina cu 1 sau 5 sau 6

7^2 = 49, u(7^4) = u(49*49) = u(9*9) =u(81) = 1

u(7^475) = u(7^3*7^472) =

              u(7^3*(7^4)^118) = u(49*7*1) = u(63) = 3

u(7^236) = u(7^4)^59 = 1

8^2 =64, u(8^4) = u(64*64) = u(4*4)=u(16) = 6

u(8^1031) = u(8^3*8^1028)=

    u((8^3*(8^4)^257) = u(64*8*6) = u(4*8*6)=u(32*6) = 2

u(8^260) = u((8^4)^)^65) = 6

u(9^2 )= u(9*9) = u(81) = 1

u(9^93)= u(9*9^92) = u(9*(9^2)) =u(9*1) = 9

u(9^150)   etc.