Question

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Answer 1

$\it a) \sqrt{\dfrac{8}{9}}=\dfrac{\sqrt{4\cdot2}}{3}=\dfrac{2\sqrt2}{3}\\ \\ \\ b)\ \sqrt{\dfrac{28}{75}}=\sqrt{\dfrac{4\cdot7}{25\cdot3}}=\dfrac{2\sqrt7}{5\sqrt3}\\ \\ \\ c)\ \sqrt{\dfrac{^{2)}3}{200}}=\sqrt{\dfrac{6}{400}}=\dfrac{\sqrt6}{20}\\ \\ \\ d)\ \ \sqrt{\dfrac{54}{25}}=\dfrac{\sqrt{9\cdot6}}{5}=\dfrac{3\sqrt6}{5}$

$\it f)\ \sqrt{\dfrac{^{4)}0,25}{12}}=\sqrt{\dfrac{1}{48}}=\dfrac{1}{\sqrt{16\cdot3}}=\dfrac{1}{4\sqrt3}$

$\it g)\ \ \sqrt{1\dfrac{7}{18}}=\sqrt{\dfrac{25}{18}}=\dfrac{5}{\sqrt{9\cdot2}}=\dfrac{5}{3\sqrt2}$