Question

Ultimele 10 subpuncte va rog urgent.. ​

Answer 1

Rezolvari:

N) x

x^{2} -11x+24=x^{2] -3x-8x+24=x(x-3)-8(x-3)=(x-3)(x-8)

x^{2} -11x+30=x^{2} -5x-6x+30=x(x-5)-6(x-5)=(x-6)(x-5)

x^{2} +9x-10=x^2-x+10x-10=x(x-1)+10(x-1)=(x-1)(x+10)

x^[2]+8x-33=x^[2]-3x+11x-33-x(x-3)+11(x-3)=(x+11)(x=3)

x^[2]+6x-16=x^[2]-2x+8x-16=x(x-2)+8(x-2)=(x+8)(x-2)

x^[2]+7x-30=x^[2]-3x+10x-30=x(x-3)+10(x-3)=(x+10)(x-3)

x^[2]-4x-5=x^[2]+x-5x-5=x(x+1)-5(x+1)=(x-5)(x+1)

x^[2]-5x-36=x^[2]+4x-9x-36=x(x+4)-9(x+4)=(x+4)(x-9)

x^[2]-6x-27=x^[2]+3x-9x-27=x(x+3)-9(x+3)=(x-9)(x+3)

x^[2]-7x-18=x^[2]+2x-9x-18=x(x+2)-9(x+2)=(x-9)(x+2)

Sper ca te-am ajutat!