Question

Un acid monocarboxilic saturat contine 48,64% C si 8,108% H. Identificați acidul

Answer 1

acidul contine C,H si O
100-48,64-8,108=43,252% O
Pasul 1: impartim rapoartele la masa atomica a elementului
C:48,64/12=4,0533
H:8,108/1=8,108
O:43,252/16=2,70325
Pasul II: impartim rapoartele obtinute, la cel mai mic, obtinand formula bruta
C:4,05233/2,70325=1,5
H:8,108/2,70325=3
O:2,70325/2,70325=1
formula bruta: $(C_{1,5} H_{3}O)_{n}$
Insa fiind monocarboxilic => are o singura gr -COOH, deci 2 atomi de o => n=2
formula moleculara: C₃H₆O₂
formula de structura: CH₃-CH₂-COOH