Question

Un amestec de 2 gaze CO2 si CO cu volumul 8.86 l . A fost ars si s-au consumat 3.36 l de oxigen. Calculati partile de volumu ale fiecarui gaz din amestecul initial

Answer 1

n=V/Vm=3,36/22,4=0,15 moli O2

2CO + O2 => 2CO2

2*22,4L CO...............1 mol O2
x L CO......................0,15 moli O2

x=44,8*0,15= 6,72 L CO

V CO2 = 8,86-6,72=2,14L

%CO=VCO/V amestec*100 = 6,72/8,86*100 = 

%CO2= VCO2/V amestec*100 = 2,14/8,86*100 =