Question

un amestec de 3 hexena si 1 butena in raport molar 2:3 se oxideaza cu Kmno4?h2SO4. Substanta organica formata se dizolva in 1896,4 g apa si rezulta o solutie 5,18%.Masa de 3 hexena din amestec a fost

Answer 1

Raport de 2:3 => 2x moli hexena si 3x moli butena
1mol......................................................2*74g
CH3-CH2-CH=CH-CH2-CH3 + 4[O] -> 2CH3-CH2-COOH
2x moli..................................................296x
1mol.........................................74g
CH2=CH-CH2-CH3 + 5[O] -> CH3-CH2-COOH + CO2 + H2O
3x.............................................222x
macid=518x
5,18/100=518x/(1896,4+518x)
518x+1896,4=518x*100/5,18=10000x
9482x=1896,4 => x=0,2moli
mhexena=296*0,2=59,2g