Question

Un amestec de 500 l contine 20% CH4 si 80% C2H6
Se cere
a. V CH4 si V C2H6
b. molii CH4 si C2H6
c. ec de ardere
d. V CO2 rez din arderi
e. V aer necesar arderii

Answer 1

Răspuns:

V,CH4=20/100X500L=100L

V.C2H6=400L

niu=V/ Vm

niuCH4=100/22,4mol=-4,545 mol

niu,C2H6= 400/22,4=17,857mol

1mol.......2mol.....1mol

CH4+2O2----> CO2+2H2O

4,545mol......x......y

x= 4,545X2MOL=9,09molO2

Y= 4,545molCO2

V.O2= niuxVm= 4,545x22,4l=101,8l

V,aer= 20/100x101.8l=20,36l aer

1mol........3,5mol........2mol

C2H6+ 7/2O2---> 2CO2+3H2O

17,857........x..............y

x= 17,857x3,5mol=62,5mol O2

y=17,857x2mol=35,714 molCO2

V,O2= 62,5X22,4 L=1400 L

V,aer= 20/100x1400l=280l

Explicație:

/Vm=